Recent content by jasonmoon

Yes, I do mean to write Icm = ml^2/3 - I meant to say that this should be used instead of ml^2/12 What I wrote for the MOI is what I think is the right formula, taking into account for the second half of the formula d= distance between com and previous com If the axis is in the center of the...

Okay. Using the parallel axis theorem, the MOI of the arm is : I = Icm + md^2 I = (ml^2)/3 + md^2 I = [2.5(0.75)^2]/3 + 2.5(1)^2 =0.468 + 2.5 = 2.968 ml^2/3 is the actual MOI for the arm because the axis is at the end of the cylinder - ml^2/12 is the formula for COM in the center of the...

From my answer above, the MOI of a skater's arm via the || axis theorems is 0.117 + 0.97 = 1.08 (0.97 is from my solution of md^2 above)

Iarm=mL2/12 therefore, I= (2.5 kg)*(0.75 m)2/12 I= (2.5)*(0.5625)/12 I=0.117

So Iarm=1/2ml^2

[QUOIowa lTE="jasonmoon, post: 4866739, member: 520129"]I thought that for b I calculated the moo of the body and the arms I used I=mr^2 for her body and 2md^2 for her armd Should I have done I=ml^2/2 for Icom?

I thought that for b I calculated the moo of the body and the arms I used I=mr^2 for her body and 2md^2 for her armd

So, for part a I did I = I cm + md^2 = 1/2 mr^2 + md^2 =1/2*45*0.25^2+2,5*0.625^2 =1.71+0.97 =2.70 part b was I = 1/2mr^2 + 2md^2 =1.71 + 5*0.625^2 =3.67 Is this correct?

I see, so I think that instead of using mL^2/2 as the MOI from the center of the rod, I just used the cylinder MOI which was completely incorrect.

Problem: Consider an ice skater spinning in a circle. We will approximate the body as a cylinder with a radius of 0.25 m. The total mass of the skater is 50kg. When the skater has her arms extended we will approximate her body as a cylinder with two rods attached. Each arm is 0.75 m long and has...

I see. Do you know how to apply the parallel axis theorem to solve this problem? This was my mistake and I didn't know how to do so.

Problem: Consider an ice skater spinning in a circle. We will approximate the body as a cylinder with a radius of 0.25 m. The total mass of the skater is 50kg. When the skater has her arms extended we will approximate her body as a cylinder with two rods attached. Each arm is 0.75 m long and has...

Homework Statement Two identical eggs of mass 0.1 kg are dropped from rest at height h. One is dropped on Earth and the other on the surface of the moon. Egg dropped on Earth experiences a force due to air resistance (F=-kv) where v is velocity of egg and k is constant of proportinality equal...