Homework Statement
How do Initial and Final Kinetic Energy depend on each other?
Homework EquationsThe Attempt at a Solution
Do they remain equal? For example for the same mass m, can we write
KE1 = KE2
1/2 m v1^2 = 1/2 m v2^2
This is it! I did what you said, and I got the exact answers!
When m is below the minimum, M will slide down
When m is above the maximum, M will slide up
&
Friction will orient itself according to motion. (Opposing motion in each case)
I now see why the answer in my original post was one of...
This is where my doubt lies. How do I determine which one is which?
You said I solved the problem for one case, but what I am thinking is that I have only arrived at the relation and from here I need to manipulate it in order to arrive at the required answer.
u is μ (coefficient of friction)...
Homework Statement
[/B]
Two blocks A and B of masses m and M are connected to the two ends of a string passing over a pulley. B lies on plane inclined at angle theta with the horizontal and A is hanging freely as shown. The coefficient of static friction between B and the plane is us. Find the...
Homework Statement
The capacitance of a spherical condenser is 1uF. If the spacing between the two spheres is 1mm, then what is the radius of the outer sphere
Homework Equations
[/B]
C = 4 pi Epsilon * ab/b-a (for a spherical capacitor)
The Attempt at a Solution
Given C = 1uF (u = 10^-6)
b-a...
Thank you! It worked!
if we consider the system between Q and P;
Tq - Tp - 0.1g - 1.9g = 2a
50 - 2(9.8+0.2) = Tp
Tp = 50 - 20
Tp = 30
This did bring out the right answer. But instead of my traditional method of drawing FBD of a body, I considered a system between P and Q and took the forces...
Homework Statement
Calculate Tension (Tp) and (TQ) (P is the mid point)
Homework Equations
T - mg = maThe Attempt at a Solution
For Q (massless rope)
Tq - 1.9g - 0.2g - 2.9g = 5a
Tq = 5(g+a)
Tq = 5 * 10 = 50N
Given answer = 50N
(Calculation of Tension for Q is clear to me, but I am...
Homework Statement
https://imgur.com/a/bvcxjNy
Homework Equations
Since the elevator is accelerating upwards,
N - mg = ma
or N = m(g+a) ------------ (1)
The Attempt at a Solution
In order to get the accelerations at that instant, I drew a tangent at that point and used v2 - v1/t2 - t1 = a...
Hi. I have three questionns to ask.
A very close point on the axis foo a current carrying circular coil (x<<<R) of radius R, the value of magnetic field decreases by a fraction of 5% with respect to the center value. The position of the point from the center of the coil is:
(a) R/10^1/2
(b)...