Thanks a lot! It shouldn't take too long at all! I've got to get going to class right now though so I'll have to send them to you at around 6:00 PM-ish. But I'll need a decent amount of juice because I'm supposed to write a report on your answers. But it shouldn't take too long at all, maybe 10...
Hi, I currently attend Queen's University, Kingston, Ontario, and I'm looking to interview an engineer over the Internet. I have all of my questions prepared, and if you'd like to answer them, that'd be great! Just let me know here and I'll PM you my questions, and then you can PM them back with...
Hi, I'm currently attending Queen's University, Kingston, Ontario, Canada, and I'm looking to interview an engineer over the Internet. I have all of my questions prepared, so if you're willing to answer them, just respond here and I'll send you a PM with my questions, and then you can PM back my...
Awesome, man. I plug x´ = –0.20 m into the right side, and both sides equal 98. Thanks a lot for the help, and good luck to you in your future endeavours (as lame as that sounds). lol
Oh yes, you're right—x´ = –0.20 m. But how do I prove this mathematically? I mean, I need to show that when the maximum is x = 0.10 m, the corresponding minimum must be x´ = –0.20 m in order for simple harmonic motion to occur. I could easily say that A = 1.5 m and that the two values must thus...
Homework Statement
When a mass is suspended from a spring, the spring reaches a new equilibrium position. The spring is then stretched downward by a certain amount x. When the spring comes back up and the mass reaches its maximum position, is the mass' acceleration zero? And what are all of...
Look back over my problem because I put in more variables:
Let's say that, after the mass is placed on top of the springs, the springs come to a new equilibrium position:
xeq = –0.05 m
This means that, if the springs are stretched 0.1 m above the reference level (the original...
I don't see how |h| = |h´|, because, at h, the force of gravity acts with the force exerted by the springs, while, at h´, the force of gravity acts against the force exerted by the springs.
Homework Statement
An object of mass m = 50 kg is placed on top of 10 vertical springs. After this, the springs come to a new equilibrium position, 0.05 m below the original one, so xeq = –0.05 m. The springs are stretched upward 0.15 m from the equilibrium position. The spring is released...
When I say "at rest", I mean when the person is not standing on it. I've edited my original post to show my work. But if the reference level is 40 cm below the horizontal, and the person bounces 40 cm up to reach maximum h, then xy` = 0? *Sigh* ... Or does the person simply bounce 40 cm up and...
Homework Statement
For my math class, I had to come up with a real-life scenario where data that is extracted from the scenario can produce a sinusoidal function, and I have to graph the function. My scenario involves a person bouncing up and down on a trampoline, while always staying in...
Homework Statement
For my math class, I had to come up with a real-life scenario where data that is extracted from the scenario can produce a sinusoidal function, and I have to graph the function. My scenario involves a person bouncing up and down on a trampoline, while always staying in...