yah you are right, its two different potential either 415 or 240.
But it does not seem to help.
I think the maximum power i can take out for each resistor is as follows (following my previous circuit)
for 22R: 498W
for 100: 430W
for 470: 350W
there is no way i could have...
As you know
in delta configuration
Phase voltage= Line voltage= So Phase-Phase is 415
If i were to connect it in Wye
Thenk phase to neutral votlage would be 240V
please see the attached print
I don't know if this information should have make difference in understanding the situation.
Since even with the 3phase balanced load the current flowing through the resistors are same. This is just delta configuration.
it does not seem to help anyway...
Problem: Construct a 3-ph resistor load bank provided the following resistors:
22ohm:500W (Quantity : 15)
470ohm:500W (Quantity:15)
100ohm: 500W (Quantity: 15)
Each power resistor should dissipate nearly 500W (full wattage) connected in series and/or parallel. The supply line...
if i were to combine then in order to have required voltages across them, the I^2 current is either goin to burn the resistor or not provide sufficient power.
thats why i am here after not been able to figure out
I don't see of combinations since P=I^2*R= V^2/R
which would be the same as i was trying to achieve current.
using P=V^2/R,the voltages across each would be
22ohm: 104.9V
100ohm:223.6V
470ohm: 484V
any idea how to combine resistors to get these voltages across it
Did you get my question this time
lets make it simple. i don't care what's the total output power going to be when all the resistors are dissipating 500W each.
for the time i just want each to dissipate 500W (or close).
With the current circuit its way to less than 500w for resistors...
ok sorry for the confusion
What i have in the attached circuit.
I will have maximum power for each as followed based on P=I^2*R:
22ohm: 489W (that would be multiplied by 4 since 4, 22ohm are used)
100ohm: 430W (that would be multiplied by 2)
470ohm: 366 (that would be single)...
there are 3 resistors of, different values. 470o,22o and 100o. but each one is 500W
I want to connect them in series/parallel in order to dissipate the maximum power 500W.
I have connected 4,22o in series and 2, 100o in series, 1, 470 in parallel. but the dissipation is not maximum.
the...