So to find C, I have to sub in a point, let's say the y-intercept? What I don't understand is where does the zero at x = -1 of multiplicity 2 go? Thanks for the reply btw
Homework Statement
-I have the zero, which is x=-1, however its a squared zero {(x+1)^2)}
-Vertical asymptote is at x=1
-Equation of oblique asymptote is y=x+4
Homework Equations
The Attempt at a Solution
I tried finding the numerator by multiplying the oblique asymptote by the...