Homework Statement
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Homework EquationsThe Attempt at a Solution
1) I determined the input impedance of the first transmission line (Zin1).
2) I calculated...
Homework Statement
Find the value of v1, v2, vab, vbc, vca. See picture
Homework Equations
Kirchoff's Law
The Attempt at a Solution
Is it true that both current through 3 and 4 ohm resistors are zero?
The way I think of this is if they aren't zero, there would be charge building up at a...
Ok I think I got it.
to prove that if ##x \in N(A)## then ##x \in N(A^t A)##.
##x \in N(A)##. By definition, ##Ax = 0##
therefore ##A^t A x = 0## which means ##x \in N(A^t A)## as well.
Therefore ##N(A) \subset N(A^t A)##.
Thanks a lot jbunniii.
Homework Statement
Given matrix A (size m x n), prove N(A) is subset of N( A^t A).
A^t is matrix A transposed.
Homework Equations
The Attempt at a Solution
My assumption is m < n, using definition of nullspace, I ended up with N( A^t A) = a set of zero vector, while N(A) is...
I am sorry, but in this case, are you saying that my prof's limit of integration is correct?
I understand that you need reference length for the force to be acting, but putting the initial limit of integration as something other than 0 would mean that you have stretched it beyond its natural...
Homework Statement
Please see attachment.
Homework Equations
The Attempt at a Solution
Not really a homework problem. This is 1 of my exam question which I believe I had the right answer but my professor insists that he has the right one.
I started by equating work done, W =...
Homework Statement
For 1st order linear ordinary differential equation, how do "unique solution" and "particular solution" differ?
Homework Equations
if dy/dx = f(x,y) and partial f(x,y) with respect to y are both continuous, then there exists a unique solution within a region R...
Homework Statement
dy/dx = (y^2 - 1)/ (x^2 - 1) with initial condition y(2) = 2
Why is y = 1 and/or y= -1 not solutions?
Homework Equations
The Attempt at a Solution
I am actually able to solve this differential equation but when I separate the equation according to x and y...