I meant for Part D that the energy was in transition between both train carts. Similar to how a spring contains the some of the energy being transferred while one cart is giving and the other is receiving.
Part E I see what you mean with the difference being 15 N between each distance.
And...
Part D - It would then be somewhere in between the touching metal of the train cars about to be transferred ?
Part E - 15 N acting at each impulse. And I think it is kinetic energy or work under the graph.
Part F - The minimum distance is .03m right ?
Part C - I take the vf from Part B and sub it into the formula for EK and use the total mass of both trains.
EK = .5mv2
= .5(7.5 kg)( .4 m/s)2
= .6 J
Part D - F - I have no clue. Help ?
Thomas the tank engine and Diesel are involved in an elastic collision. A 2.5 kg Thomas is at rest but is approached head-on by a 5.0 kg Diesel moving at 0.60 m/s.
The force-separation graph for the ensuing collision is given.
FYI I am terrible with graphs, IDK WHY.. :frown:
mT =...
A .5g insect rests on a compact disc at a distance of 4cm from the centre. If the coeffiecient of static friction is .51 what is the maximum velocity the insect can experience without slipping off?
I am lost, can someone help ?
Calculate the tension in the cable connecting the two masses. Assume all surfaces are frictionless.
FBD
m1 = 5 kg
θ1 = 60°
m2 = 6 kg
θ2 = 70°
Equation 1 ~
FT - Fg = ma
FT - mgSinθ = ma
FT = 5a + 5(9.8)Sin60
FT = 5a + 42.44
Equation 2 ~
Fg - FT = ma...
In the following diagram there is a coefficient of friction, μ, of 0.15 between the 5.0 kg mass and the surface. Calculate the tension in the cable connecting the two masses and the resulting acceleration.
FBD
m1= 2 kg
m2= 5 kg
μ= .15
g= 9.8 m/s2
Equation 1 ~
Fg - FT = FN...
Alright, so assuming everything so far is correct, my only issue has been the angle at which the bullet hits the ground.
If Tan θ = O / A then could I use the components for Sin and Cos ?
My text says that I should change the Velocity of the Vertical Component by using:
Vr = Vy + aΔt...
First off, doesn't a Muzzle Velocity seem a bit low at 120 m/s? -_-
Alright, so it looks like I end up with a Quadratic and solve for both values.
0 = -4.9t^2 + 60t + 35
t = -.55s and 12.8s
But there can't be negative time, amiright ?
And I am unsure about the Total change in the...
A sniper fires a bullet at 120 m/s at 30° above the horizontal from the roof top of a 35 m high parking garage. If the bullet strikes the level ground beside the parking garage:
How long was the bullet in the air?
How far from the base of the parking garage did the bullet land?
At what...