For A the 1.2 kg block is being pulled by gravity hence work is done downwards which will make work positive since it's going with the same direction as the force.
1.2 * 9.8 = 11.76 N pulled downwards
Work = F*d
11.76*0.75 = 8.82 J
The tension is the other force and since the thing is...
I did this too fast idk if I'm wrong
So for the x component
use the formula d = rt / delta x = v*t
26 = vcos(theta)
y component
use the displacement formula
19.6 = vsin(theta)
tan^-1(19.6/26) = 36.5 degrees
the answer key says 20.2 degrees idk whats wrong
I think i get it now.
6.78 is the initial velocity at the top of the door
To find the height of the ladder I would have to make 6.78 the final velocity, and the initial velocity 0
I find the time between the rock dropping from the top of the ladder to the top of the door.
Then using the...
When I drop a rock from the top of my ladder, I notice that it takes 0.25 seconds for the rock to fall past our
2-m tall door and hit the ground below. What was the velocity of the rock when it passed the top of the door?
How tall is my ladder?
You're suppose to take -6.78 m/s as the final...
I am super stumped at this question, the answer key is telling me 6.78 downwards, i think I'm reading and observing the question wrong. Isn't final velocity 0 so why can't i do
0 = v0 -9.8(0.25)
-2.45 = v0
But when I use the second the equation
-2 (displacement of door) = v0(0.25) + 1/2...
My answer is R > P > Q = S
Since R is more steeper than P the speed is greater, speed is a non-negative unit so i assume that speed of R will be greater than P
Speed of P has a positive slope, also the magnitude is positive.
Q and S are the same due to the fast that they both horizontal slopes...