By your response, I assume then that this appears not to be in the literature. Which was actually my original question. And no, I did not use h in the calculation. I was only explaining that Doc Al's difference in expected value of E from eV.
Although that does make me think. Doesn't the value...
Sure
2.12 EV * 580nm = 1229.60
122960^2 = 1511916
1511916 x 2 = 3023832
3023832 / 299792 = 10.086434
I scaled the answer as I originally used it to make a graph.
This concept of 1.6 is because in the equation W= c*h / f provided previously need to be divided by e (roughly 1.6) to produce...
I am sorry, by 1.6, I mean the electrical charge constant e. Those are the values I am showing in the data set. When you multiply the threshold wavelength, by the work function in EVs and square the result is very nearly is equal to half the speed of light. I don't think it's numerology.
It...
OK, maybe I should supply some data. here is a list of some of the elements i checked.
Element
W (Ev)
λ
Multiplied
Cs 55 (s)
212
580
122.9
Na 11 (s)
227
540
122.5
Ba 56 (s)
251
490
122.9
Mg 12 (s)
346
350
121.1
Zn 30 (D)
374
330
123.4
Al 14 (P)
374
330
123.4...
Thanks.
But do you know where I can find the equation in the literature. As this provides a wave solution to the photoelectric effect, I am sure it must be an important concept in science, right?
I mean, regardless of the name, I just want to find out more about it.
I was recently examining the relationship between the work function of a material and its threshold wavelength. It was clear to me that the relationship is expressed as:
(λW)² = c/2
Where λ is the threshold wavelength, W is the work function, and c is the speed of light. However, I am unable...