yes Tiny-tim,
actual answer is
\frac{\partial (z/r^3)}{\partial z } = \frac{1}{r^3} - \frac{3z^2}{r^5} tiny-tim, as you told me i did partial differentiation using quotient rule and chain rule
and i got
\frac{\partial (z/r^3)}{\partial z } = 1/(r^3) - (3z)/r^4 \frac{\partial r}{\partial...
Thank you tiny-tim,
after doing partial differentiation and chain rule i got following.
d (z/r^3)/dz = 1/[r][/3] - 3z/[x^4] * dr/dz
but actual answer is 1/[r^3] - 3z^2/[x^5]
Mathematical method in electrical potential ??
Hi All,
I need mathematical help from the topic electrical potential for lectures on physics by Richard Feynman.
Need some help to understand mathematical method used here.
question :
1) From electrical potential.png
( how this partial...
what is the difference between canonical and conjugate momentum.. ? what is its physical significant.. I was reading classical mechanics by Goldstein but could understood this terms