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    How Does ((n+1)^2 * n!) / ((n+1)! * n^2) Simplify to (n+1) / n^2?

    How can ((n+1)^2(*n!))/((n+1)!*n^2) be simplified to (n+1)/n^2? My own answer is (n+1)^2/n^2, but its apparently wrong
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