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    Gravitational Forces on three masses at the corners of an equilateral triangle

  2. hasibx

    Gravitational Forces on three masses at the corners of an equilateral triangle

    I solved the math using vector rule R= \sqrt{F^2 +F^2 +2F^2cos\frac{\pi}{3}} =\sqrt{3}\frac{Gm^2}{a^2} But the answer is showing: \sqrt{3}\frac{Gm^2}{a^2} (-\hat{j}) My question is: Why is (-\hat{j}) added here? Why is it negative?
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