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In the Arctic, if I had 10 vertical meters of 1 degree Celsius water above freezing brought to the surface, how much ice would that melt?

Homework Statement Come up with the frequency directly from the solutions of the characteristic equation. {{z=0.-5.71839 i},{z=0.+5.71839 i}} Homework Equations characteristic equation = z^2+b z+c=0 The Attempt at a Solution Not sure where to start. Any help would be greatly...

Homework Statement

hallsofIvy: Yes, it's suppose to be y'(t)+ y(t)= 0

Homework Statement I have three diff eqs: a) y'(t) + 2t y(t) = 0 b) y'(t) - 2t y(t) = 0 c) y(t) + y(t) = 0. I'm trying find which of these diffeqs is solved by y(t) = 8 E^-t^2 ? Please Help!

Makes sense. Thanks micromass

Homework Statement y1[t] solves y't]+9.7 y[t]=E^(-0.4 t) Cos[t], with y[0]=0, and y2[t] solves y'[t]+9.7 y[t]=0, with y[0]=1. What numbers p and q do you pick to make y[t]=p y1[t] + q y2[t] solve y'[t]+9.7 y[t]=3 E^(-0.4 t) Cos[t], with y[0]=3...

1. Homework Statement When a condenser discharges electricity, the instantaneous rate of change of the voltage is proportional to the voltage in the condenser. Suppose you have a discharging condenser and the instantaneous rate of change of the voltage is -0.01 of the voltage (in volts per...

Homework Statement When a condenser discharges electricity, the instantaneous rate of change of the voltage is proportional to the voltage in the condenser. Suppose you have a discharging condenser and the instantaneous rate of change of the voltage is -0.01 of the voltage (in volts per...

Homework Statement I was given three plots of solutions for a forced exponential diffeq: y'[t]+1.85 y[t]=0.7t^2 with starter values on y[0] equal to -6, 0,and +7 The three plots eventually merge, how do I give the formula for this parabola? Homework Equations E^(-r t)...

I was given three plots of solutions for a forced exponential diffeq: y'[t]+1.85 y[t]=0.7t^2 with starter values on y[0] equal to -6, 0,and +7 The three plots eventually merge, how do I give the formula for this parabola?

Mark44, That helped. Thanks. What changes when the differential equation is (y^\[Prime])[t]= - 0.2 y[t] + Sin[t] with y[0]=15.3 and I need to come up with the formula for y[t]?

Mark44, So, I can chose whatever co-effiecients I want?...to test it.

Ok. So, y'[Asin(t) + Bcos(t)]+0.2y[Asin(t) + Bcos(t)]=sin[t]?

Would yp= y'[t]+0.2y[t]-sin[t]= Asin(t) + Bcos(t)?