Recent content by Gionata

  1. Gionata

    I Recursive square root inside square root problem

    = RADQ (2 + D10 * RADQ (2 + D10)) = 2.2534 different = RADQ (D10 + 2 * RADQ (D10 + 3)) = 2,4322 the value of pi I wish before the sequence 2,3,(n)
  2. Gionata

    I Recursive square root inside square root problem

    Strange, I calculated manually with excel the first 10 series: I got: 3.128171204 D2= 1.6180339887 (phi) =RADQ(D2+2*RADQ(D2+3*RADQ(D2+4*RADQ(D2+5*RADQ(D2+6*RADQ(D2+7*RADQ(D2+8*RADQ(D2+9*RADQ(D2+10))))))))
  3. Gionata

    I Recursive square root inside square root problem

    I calculated that for phi (Golden section) f(0)=2.267712876 But it is not correct: http://www.wolframalpha.com/input/?i=f\left(n+1\right)=\frac{1}{1.6180339887}\left(f\left(n\right)^2-n-1\right);+f(0)=+2.267712876 What's wrong?
  4. Gionata

    I Recursive square root inside square root problem

    Super Super! Thanks a lot for your help !
  5. Gionata

    I Recursive square root inside square root problem

    oh, my error ignores... Question, if I want to replace (retaining the formula) only the pi with phi example, and doing all the calculations as we did together should work? ##\large{\sqrt{2+\phi \sqrt{3+\phi\sqrt{4+\phi\sqrt{5+\dotsb}}}}}##
  6. Gionata

    I Recursive square root inside square root problem

    well, understood thank you very much! Last question just to understand: f(0)= 3.609993083 http://www.wolframalpha.com/input/?i=f%5Cleft(n%2B1%5Cright)%3D%5Cfrac%7B1%7D%7B%5Cpi%7D%5Cleft(f%5Cleft(n%5Cright)%5E2-n-1%5Cright);+f(0)%3D+3.609993083 ##\sqrt{2+\pi }## f(0) should not give 2.26751...
  7. Gionata

    I Recursive square root inside square root problem

    I am really happy that it works, after days of work. Thanks for the explanations, you have a great talent. You asked me if I can generate f(9,000) in MatLab, the answer is no, do you want to explain it to me? That would be the culmination of the project.
  8. Gionata

    I Recursive square root inside square root problem

    for f(99)= 11.70016315 for f(0)= 3.609993083 Correct?
  9. Gionata

    I Recursive square root inside square root problem

    well now I've understood the situation, I have to find the key value of f0), but I'm currently struggling a lot, if you're patient and want to I'd like if together you help me to calculate the value of f(0). I would be very grateful.
  10. Gionata

    I Recursive square root inside square root problem

    I am a looking for a recursive formula in the form of: ##f\left(n\right)=\sqrt{n+1+\pi f\left(n+1\right)}## in alternative ##f\left(n+1\right)=\frac{1}{\pi}\left(f\left(n\right)^2-n-1\right)## These examples mentioned above are very close to the solution but unfortunately wrong. What I want...
  11. Gionata

    I Recursive square root inside square root problem

    Thank you very much for the very comprehensive response. I need the recursive formula because I have to demonstrate with another program (mathlab) that at high sequnze of n (very high) the value tends to a value x. To do this I cannot be satisfied with an approximation but rather with a...
  12. Gionata

    I Recursive square root inside square root problem

    I have been debating this issue for days: I can't find a recursive function of this equation: ##\large{\sqrt{2+\pi \sqrt{3+\pi\sqrt{4+\pi\sqrt{5+\dotsb}}}}}## Starting value 2 always added with pi has been trying to find a solution this for days now, is what I have achieved so far: This...
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