So essentially $$\bar{2}.8041$$ means only the number under the bar is negative and the rest is positive whereas $$-1.1959$$ means the entire number before and after the decimal is negative?
From the log tables:
##log(890) = 2.9494, \space
log(12.34)=1.0913, \space
log(0.0637)=\bar{2}.8041##
I calculate by hand:
##\begin{array}{r}
&2.9494\\
+&1.0913\\&\bar{2}.8041\\\hline &2.8448
\end{array}##
Thus:
##log^{-1}(2.8448) \approx 699.6 \space##
Which is the correct answer.
Now I...