my course work supplied me with a table for gas enthalpy at various temperatures. I didn't do ant equations here. I just simply used the data from the table.
then used the theory of heat in = heat out. My heat in I calculated to be 2581kj. Then i tabulated the output estimates which were within...
N2 = 66.1 kj / mol is the enthalpy at 2000°C
This is how I have derived the maximum flame temp. to be 1987°C. Then from this obtained the heat capacity.
what do you make it?
Hi chestermiller.
Its the flame temperature.
I calculated the flame temperature to be 1987°C. (which might also be incorrect).
what do you make it?
Regards.
Homework Statement
A fuel gas consists of 75% butane (C4H10), 10% propane (C3H8) and 15% butene (C4H8) by volume.
It is to be fed to the combustion chamber in 10% excess air at 25°C, where it is completely burnt to carbon dioxide and water. The flue gases produced are to be used to generate 5...
butane = -2660 kj/mol
propane = -2046 kj/mol
butene = -2540 kj/mol
heat released by 1 mole of fuel
= (0.75x2660)+(0.1x2046)+(0.15x2540)
=2581 kj (heat in)
is this correct so far?
Homework Statement
A fuel gas consists of 75% butane (C4H10), 10% propane (C3H8) and 15% butene (C4H8) by volume.
It is to be fed to the combustion chamber in 10% excess air at 25°C, where it is completely burnt to carbon dioxide and water. The flue gases produced are to be used to generate 5...
Excellent. Thanks chestermiller
My previous attempt was a country mile out then.
what about the net calorific value (CV) per kmol of the fuel/air mix at 25°C ?
Any ideas?