Well, just because we all use the english language doesn't mean it we cannot have some sort of miscommunication. If you read the above post, there was a miscommunication of the work "inaccurate". I know what real numbers are, but that is rather irrelevant to the argument I was establishing...
It just depends on your notion of time, and what it effects. You have to consider, KE in not relative. to clear this up, it is though that ALL things tend to slow down at high velocity, because of the dilation in time. The truth is that we don't exactly know what time is, we just observe it...
So, I guess it was a miscommunication of words on your behalf. I was not trying to prove that a number can occur beyond infinity, I was trying to ask why not? With all this said, it would be wrong to say .9~5 meaning an infinite nuber of 9's to the right of the decimal, with a 5 at the end...
OK, I understand it a lot more now. I am just confused with one remark from matt grime.
You said that it can be accurate to have a number after infinity, but it is not accurate to have a number at the end of infinity when talking about decimals. What do you mean by that?
My answer is...
Why must such a simple thing be so complicated? When I meant is that it is innacurate to say that a number can occur after an infinite number.
BTW, you express an infinite number by ()? like 1/3=.(3)?
what I meant was this. If we have .999.../2=.4999...with a 5 at the end, then the (9) is not really infinite. I lamen terms, if there is a number after the 9, the 9 is finite
I have no idea where you get these absurd and inaccurate remarks from, so I will break it down for you, maybe you can understand it in lamen terms.
.9/2 = .45
.99/2 = .495
.999/2 = .4995
.9999/2 = .49995
So, my question was what is .999.../2? now, if you have not realized already...
Sorry for the double post, it is just that I posted it, and then it did not show up when I refreshed the page, because the post was on page 2 of the thread, lol.
OK, so we have established that .999.../2 = .4999...? And the "5" at the end is rather imaginary, because you cannot have a number...
OK, can you please tell me then what .999.../2 is? I though that dextercioby confirmed my theory, unless you know the answer to this rather simply math problem?
Well, I did not put \infty by itsself. What I meant by .9\infty
is .999...~
So, let me ask this. If \frac {.999\infty} {2} does not equal \frac {1} {2}, instead, 4(9)5, then .999... does not equal 1?
i
So, what is the text-based or ASCII form of expressing \infty? Let me give this example.
.9/2 = .45
.99/2 = .495
.999/2 = .4995
.9999/2 = .49995
.9\infty = ? perhaps .49\infty with a 5 at the end. Is this wrong? Is it inccorect to assume that a number can be after infinit?
Ya, I just use "i" because I don't know what else to use. Can you please tell me what to use to represnt infinite? And I though about it, there is NO square root if -1, hehe. Because a negative times a negative equals a positive, and 1 is the standard unit, so I guess i means "imaginary". I...