Well, since v0 = v(0), then wouldn't v0 = e^C? I guess that makes sense to me now. Thank you.
On another note, where can I learn how to use the hashtags and other code you used to make the equations look nice?
Okay, so then after integration we get
t = -m/b ln v + C
t - C = -m/b ln v
-(t - C)b/m = ln v
(C-t)b/m = ln v
e^(C-t)b/m = v
(e^Cb/m) * (e^-tb/m) = v
does that look right?
Exactly. What I'm trying to understand is how is the equation derived so that the v0 appears in it. You are correct that the answer I came up with gives a nonsensical answer.
Maybe I'm not understanding you, or you are not understanding me. There is no solution given at time t = 0. The whole point of the problem is deriving the equation that shows the velocity as a function of time.