Thanks for the info. I have been applying the formula and have some answers, X0 using Xo=3.V^2/Q gave me 48.41W at maximum stator voltage of 230V. I thought the inductance here would be almost equivalent to the magnetic losses , i.e. the stator power. With the formula why is the voltage squared...
This makes sense
This is where i have become a bit confused. I have plotted my own curve (used to answer question i.) using the data given and i am unsure how you have managed to conclude the wining and friction losses from this graph?
1.732 is just √3 , which is in the equation as it is a three phase supply i think. If cosϕ is power factor in this scenario I am confused as to what that would make sinϕ?
The study material says under 'Estimation of magnetising losses' :On no-load, the rotor current is very small and the slip almost zero. Therefore, R′2s is very high and virtually no current flows through the branch of the circuit containing R′2s. Consequently, the no-load current is virtually...