"The flaw in this "real life" logic is that "coasting" most of the distance disippates energy (speed) via rolling friction and air resistance before the brakes are applied. "
Since you are traveling the same total distance, is there a difference between coasting at a lower speed vs a higher...
What about simply from a energy perspective, does friction/deceleration differ in aiding the braking of the vehicle depending on which speed the vehicle is coasting at (longer distance coasting @ higher speed vs shorter distance @ slower speed).
Hey guys, I have been having trouble trying to reason out in relation to real life application.
Problem:
Two vehicles (1,2) are traveling at 60mph approaching a red light 300 meters ahead. First let us state that both vehicles have the same starting & ending points, as well as the same final...
REVIEWING OLD TEST and.. don't understand why you use the full distance.
Homework Statement
pretty much there's a home made capacitor made by two pie pans 3.5 cm apart. V is given Q is given, the question asks:
calculate the electric field halfway between the plates
Homework Equations...
oh that is quite true, shouldn't have overlooked that, so i can now say the formula is
c/fd = 343/fd?
edit: yes i can, thanks a lot nickjer, i got it now.
SOLVED
Homework Statement
A two-slit interference set-up with slit separation d =0.30 mm produces interference fringes at a particular set of angles THETAm (where m = 0, 1, 2,) for red light of frequency f = 4.9×10^14 hz.
If one wishes to construct an analogous two-slit interference set-up...
im not too sure, what i would probably work towards would be:
well it took the object .210 seconds to move 1.35 meters, so find out that initial velocity (when it first is visible from the window)
then you can use the velocity you solved for (when the object is at the top of the window/ first...
so, the difference in length between the P and the M is .00003m.
so what youre looking for will be the temperature at which the ∆Lp is different by ∆m by .00003m. (since when the plate is .00003 meters bigger, the marble will fit through.)
so ∆Lp-.00003m = ∆m
(it is minus the difference...
it doesn't matter what temperature it starts at, DELTA T is just the change in temperature, so if it went from 0 to 10 or 900 to 910 DELTA T would still be 10.
[b]1. i have the answer, but just don't understnad it
A small metal ball is given a negative charge, then brought near (i.e., within a few millimeters) to end A of the rod. What happens to end A of the rod when the ball approaches it closely this first time?
Select the expected behavior...