Recent content by friendbobbiny

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    Linearising Cosine: Taking Roots of Equation

    In that case, my approach works! Have you read into finding a linearization by taking a derivative at some point of interest (or at any point of interest)?
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    Why this maximization approach fails?

    NVM set \frac{\nabla f}{|\nabla f|} to <root(2)/2, root(2)/2> Resolved!
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    Why this maximization approach fails?

    Homework Statement Find all points at which the direction of fastest change of the function f(x,y) = x^2 + y^2 -2x - 2y is in the direction of <1,1>. Homework Equations <\nabla f = \frac{\delta f}{\delta x} , \frac{\delta f}{\delta y} , \frac{\delta f}{\delta z}> The Attempt at a Solution...
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    Linearising Cosine: Taking Roots of Equation

    Hi Agrajag, what do you mean by linearize? I usually understand "linearization" to mean: find the closest linear approximation to the given curve. This can be found by taking the derivative at a point to be the slope of a line that goes through that same point. This line is your linearization.
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    Can s oribtal electrons only drop to other s orbitals?

    Why can't a drop to s take place? I infer that a drop to p(l = 1) can take place because \Delta l = 1.
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    Can s oribtal electrons only drop to other s orbitals?

    Just a thought: The momentum quantum number given for s states is l = 0. If an S state electron dropped in energy, and emitted a photon with l = 1, what would take place? Am I correct that the electron could only drop to a lower l = 0 (an S state) orbital?
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    Calculate the rate of probability density's movement?

    I understand why waves would travel rightwards. Why would they travel leftwards? To travel leftwards, a wave would have to first tunnel through the barrier and then tunnel back. A wave wouldn't tunnel back, because once it tunnels rightwards (ie. exits the barrier), it is unenclosed and will now...
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    Calculate the rate of probability density's movement?

    1. Homework Statement Given the following diagram of a finite potential well, calculate the rate at which the right-going wave is bringing probability density up to the barrier. (Ignore interference with the left-going wave. ) (Hint: you can get the velocity from the energy, and the average...
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    A Thought Experiment: Photons Passing through Detectors

    Ah, so through the double slit experiment and similar ones, interference is never produced as a result of distinct waves superimposing but through photons interfering with themselves. I should take this away, no?
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    A Thought Experiment: Photons Passing through Detectors

    I haven't encountered this in my reading. Can you explain a bit more or perhaps link me? Why would the noise term occur? I should clarify that this thought experiment used monochromatic light -- so wouldn't photons start off in phase?
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    A Thought Experiment: Photons Passing through Detectors

    However, can't one photon interfere with another one? Shouldn't we observe an interference pattern from the superimposition of photon wavelengths having different path lengths (i.e. have something close to what's below)...
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    A Thought Experiment: Photons Passing through Detectors

    Pretend we have a multi-slitted grating whose slits are infinitesimally small. We On each slit is a detector. If we shine (UPDATE) light monochromatic light through the grating, what distribution pattern occurs on the screen past the grating? I understand the train of thought to a slight...
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    Why do we use i to represent phasors and/or vectors?

    Somestimes, vectors (e.g <3,4>) are represented with a real and imaginary component (3 + 4i). When expressing wave phasors as vectors, this is usually the convention. Insofar as phasors and waves go, what rationale does the convention have? If I had to superimpose two waves together, and...
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    Acceleration of stone caught in tire tread

    Wouldn't the stone be moving leftwards, even if slightly? My impression is that you wanted me to recognize that because "the stone is still almost at ground level", its positioning really hasn't changed. If it's positioning hasn't changed, its only acceleration is upwards?
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    Acceleration of stone caught in tire tread

    So: Because the wheel picks up the stone at a point momentarily at rest, there is no rightwards acceleration? The instantaneous center of rotation occurs at the wheel's center, no? What does this suggest?
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