I appreciate everybodys help but i still seem to be getting nowhere. This is what I've got from all the advice given:
\SigmaM(x)c=0=R1a-R2b+\muh
and
R2(reaction at front wheel)=mga+\muh/a-b
Hello. Could someone possibly help me with this question?
1. The problem:
The attatchment depicts a truck which has a centre of mass C.
• The truck is front wheel drive.
• The geometrical position of C is defined.
• The coefficient of friction between the tyres and the road is μ.
•...