that's a typo, should be:
$$\sqrt{\frac{2 * 1.6 * 10^{-17}}{9.11 * 10^{-31}}} = 5,936,739$$
I've dealt with energy and I get the same thing. Either way, it should work with velocity.
I was looking at a sphere that has a positive point charge at the center of a sphere with radius R. Now, I understand that the electric field is pointing outwards (in the direction of dA), so
$$d\phi = EdA$$
However, I am told that since the magnitude electrical field is the same because the...
I have the following problem:
So, I know the following:
##q_1 = -e##
##q_2 = -e##
##q_4 = -e##
##q_5 = e##
##e = 1.6*10^{-19}##
##k = 9*10^{9}##
Now, I can get the current ##F_{net}## of particle 5 with this information:
##F_{net} = (F_{3} - F_{1})\hat i + (F_{2} + F_{4})\hat j##
##F_{1} = k...
Alright, so if I use conservation of energy:
(1/2)mv^2 = mgh
v = (2gh)^(1/2)
The height would be h = (L^2 -x^2)^(1/2)
so the Velocity = (2g * (L^2 -x^2)^(1/2))^(1/2)
That doesn't show up on the answers.