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• Today, 03:50
That works. (Nod) Note that $f(x)=\frac{1}{3}(x-2)^2e^{x/3}$ is hard to match with a line, since it has an exponential function in it. However,...
3 replies | 37 view(s)
• Today, 03:16
Put a +C at the end of your indefinite integral, and then you are correct.
1 replies | 19 view(s)
• Today, 02:27
Look at the numbers. Can you divide by 0? Can you take an even root of a negative number?
6 replies | 107 view(s)
• Yesterday, 18:07
I appreciate another take on the sites that I have listed. The more views I get from you all, the better. I view the way MHB goes as a group decision...
6 replies | 217 view(s)
• Yesterday, 17:20
Hey mathmari!! We could, but perhaps the intersection points are "nice" points. What are the potentially nice points? (Wondering)
3 replies | 37 view(s)
• Yesterday, 11:06
The problems with MHF were always about personnel and authority structure. If the leaders of MHF had been willing to appoint multiple admins, like we...
6 replies | 217 view(s)
• Yesterday, 09:27
Yep. (Nod)
4 replies | 73 view(s)
• Yesterday, 07:06
First we need to write the DE as a system of first order DEs. Let $\displaystyle u = y$ and $\displaystyle v = y'$. Then $\displaystyle... 0 replies | 40 view(s) • Yesterday, 06:42 We would need to recognise that the integral in the equation is a convolution integral, which has Laplace Transform:$\displaystyle...
0 replies | 30 view(s)
• Yesterday, 06:26
Taking the Laplace Transform of the equation gives \displaystyle \begin{align*} s^2\,Y\left( s \right) - s\,y\left( 0 \right) - y'\left( 0... 0 replies | 21 view(s) • Yesterday, 02:53 Thank you for pointing this out. I have not looked at other sites in a long time so don't know these things. If a merge was possible I promise I... 6 replies | 217 view(s) • Yesterday, 02:24 I'd be worried about a merge, the spam on MHF is out of control and has been for years, and I have concerns that should we merge, the same thing... 6 replies | 217 view(s) • Yesterday, 02:01 Hey firemath, Thank you for the reply. It's great to hear back from someone on this tough topic. I actually strongly prefer a merge over other... 6 replies | 217 view(s) • April 7th, 2020, 17:57 When I throw it at Octave online, I get: So it seems it is none of the above, but the answer3$is close. For reference, I have re-encoded... 1 replies | 72 view(s) • April 7th, 2020, 14:20 Let$f:\mathbb R\to \mathbb R$be a twice-differentiable function such that$f(x)+f^{\prime\prime}(x)=-x|\sin(x)|f'(x)$for$x\geq 0$. Assume that... 1 replies | 72 view(s) • April 6th, 2020, 16:33 What do you mean "there is no graph on the positive side"? Of couse there is. 6 replies | 107 view(s) • April 6th, 2020, 16:12 How many "capsules" are there on the Ferris wheel? 2 replies | 72 view(s) • April 6th, 2020, 12:06 Hi all, I think even we do switch to XF (is still going to happen) the time has come to make a change. We have a database of amazing content here... 6 replies | 217 view(s) • April 6th, 2020, 11:37 Hi all, I hope you are all safe, healthy, and not affected in a serious way by the world wide COVID-19 virus. Here in the US it has completely... 0 replies | 62 view(s) • April 6th, 2020, 11:34 Hey mathmari!! This is an example where Newton-Raphson can have problems if we are not careful. If we pick a starting value that is too far from... 4 replies | 73 view(s) • April 6th, 2020, 10:30 \frac{\left(x\sin\left(\pi\left(x-1\right)\right)\right)}{e^{x/9}(x-1)} The above graph shows that the function repeats its value at$x=1$when$x$... 4 replies | 73 view(s) • April 6th, 2020, 01:44 Why are you plugging in large negative values for x? Surely for an infinite limit you should be plugging in large positive values. As for a hint,... 6 replies | 107 view(s) • April 5th, 2020, 20:46 Prove It replied to a thread [SOLVED] Limit of exponential function in Pre-Calculus This is a$\displaystyle 1^{\infty} $indeterminate form. It can be transformed into a form that can use L'Hospital's Rule by$\displaystyle...
7 replies | 288 view(s)
• April 5th, 2020, 10:37
I substituted $n=\frac 1{x^2}$, which also means that $x^2=\frac 1 n$. So we get $\Big(1 + \frac 32 x^2\Big)^{1/x^2} = \Big(1 + \frac 32 \cdot \frac... 7 replies | 288 view(s) • April 5th, 2020, 10:02 Since this is of the form$\displaystyle \frac{f\left( t \right)}{t} $we should use$\displaystyle \mathcal{L}\,\left\{ \frac{f\left( t \right) }{t}...
0 replies | 55 view(s)
• April 5th, 2020, 09:15
To apply this Runge-Kutta scheme, we will need to write our second order DE as a system of first order DEs. Let $\displaystyle u = y$ and...
0 replies | 46 view(s)
• April 5th, 2020, 09:14
It's like this: \Big(1-\frac 12 x^2 + \ldots\Big)\Big(1+\frac 12 (2x)^2 - \ldots\Big)\\ =1\cdot 1 -\frac 12 x^2 \cdot 1+1\cdot \frac 12 (2x)^2 -...
7 replies | 288 view(s)
• April 5th, 2020, 08:53
The Bisection Method solves equations of the form $\displaystyle f\left( x \right) = 0$ so we must write the equation as \$\displaystyle 11\cos{...
0 replies | 193 view(s)
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### 25 Visitor Messages

1. Hello and welcome back to MHB, Fantini!

We are happy to see that you have returned, and we look forward to your continued participation here!

On Behalf Of MHB's Staff,

Ackbach.
2. Thanks Fantini
3. Haha. \widehat's cool. Also check out \widetilde. But these sometimes get ugly.
4. Yep. Corrected now.
5. Thanks for the thanks. For what it's worth, I have already let Jameson know that an option to turn off or disable the social media buttons would be a good idea in my opinion.
6. Hey, good catch...that is in fact what I meant to type, but my darn keyboard seems to have a mind of its own at times. Thanks for letting me know so I could fix it.
7. Yes thanks Fantini, edited
8. Not at all...it's GOOD to think about these things.
9. Fantini, have I seen you on SE before?
10. Fantini - Hey, thanks! Yeah, the colors go well together, I think. Bach was the greatest!
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