Recent content by fanie1031

1. The total cross-sectional area of the load-bearing calcified portion of the two forearms bones (radius and ulna) is approximately 2.16cm^2. During a car crash, the forearm is slammed against the dashboard. Tha arm comes to rest from an initial speed of 81.9km/h in 7.72 s. If the arm has an...

I have this question also The equation for the period of oscillation: T=2pi* square root (L/g) Once you find T Solve for w [w=2pi/T] Then I thought of using the velocity formula: v=Aw But... I'm not sure how to find the amplitude. Can you guide me in the right direction?

I have the same problem. I set it up two different ways. v^2=k/mA^2-K/mx^2, then square root A-full amplitude X-half the amplitude or v=[(k/m)(A^2*X^2)]^(-1/2) but none worked. I'm pretty sure I'm setting up the amplitude stuff wrong.

Oh I got it. Thank you. Delta t= m(Vf-Vi)/F.

Dang, I don't know what you mean by u in Ft=mv-mu=m(v-u). The change in velocity is definitely something I missed. THank you for pointing it out.

Oh in 2. It should be F= m(delta v/delta t)

1. Small rockets are sued to make small adjustments in the speed of satellites. One such rocket has a thrust of 59N. If it is fired to change the velocity of a(n) 74000kg spacecraft by 54cm/s, howl ong should it be fired? Answer in units of s. 2. F=deltaP, delta t; F=mVf-mVi...

1. A spring of constant 22 N/m is compressed a distance 8 cm by a 0.4kg mass, then released. It skids over a frictional surface of length 2.3m with coefficient of friction 0.17, then compresses the second spring of constant 2N/cm. The acceleration of gravity is 9.8m/s(squared). How far will...

Oh thank you for going ahead and writting up the solution.

OOh I got it! I did this: v=[2(gVi-gVf)]^(1/2) You sparked my thinking. Thank you.

I'm using .5 as her initial height and 3 as her final height. Is that my problem? And velocity... I just assumed... that may be wrong. (Thanks for the quick reply by the way!)

[b]1. A girl swings on a playground swing in such a way that at her highest point she is 3 m from the ground, while at her lowest point she is 0.5m from the ground. The acceleration of gravity is 9.8m/s^2. What is her maximum speed? Answer in units of m/s. [b]2. 1/2mVf^2 + mgyf =...