Got it .. I placed a small mirror in a pot and filled it with water. The pot is 200+ mm tall and I was able to see dispersion. It's not very clear in the picture, but you get the idea.
Photo-0010 by Cristi .eXPV, on Flickr
So you would need a mirror 25 cm thick in order to see clear...
Let's say we look at an object that reflects only 3 components in visible spectrum at a large distance from one to another (i.e. red, yellow, blue). What I should see in the mirror are 3 images of the object, corresponding to each color, that are slightly displaced.
I looked in a mirror as...
I was just wandering, why when I look through a glass or a mirror at 45 degrees related to it's surface normal I don't see a rainbow/blurry image?
Here is a picture that hopefully, describes better what I mean.
Dispersion by Cristi .eXPV, on Flickr
I think I got it. I don't know why but when a b term gets negative the remainder has to be made positive using 3th method. Then the next remainder has to be made negative using 2th method if x is positive or 1th method if x is negative.
There is an article on wikipedia (http://en.wikipedia.org/wiki/Fourier_division" ) about Fourier division algorithm, but there is something that confuses me.
When they compute the so called "b terms" they have to divide 2 numbers. Let's call them x and y, and x/y=q+r. To compute q and r they use...