i am faced with some homework in Resolve/C++ and encountered several problems
ensures
t1 = #t1 * #t2
-what do the pound signs before the variables mean?
-what does it mean when one text "*" another text?
hope someone can help. can't really find much resolve/C++ help online. thanks!
Homework Statement
A sailboat is traveling east at 4.5ms-1. a suddent gust of wind gives the boat an acceleration a = 0.70 ms-2, 40 degress north to east. what are the boat's speed and direction 6s later when the gust subsides?
Homework Equations
V(@6s) = V(init.) + at
The Attempt at a...
i understand the part where there is only one accel. but how can i get the y(11s)? all i have is the position after a 4s freefall, and to start with the freefall has an initial velocity.
ok that was quite a mess.
V(@11s) = V(init.) + At = 0 + (a - 9.8)11 = 11a - 107.8
therefore the distance the rocket fell after motor has stopped (ie ignoring distance already travelled) is:
S = S(11s, ignore) + V(@11s)t + .5(-9.8)t^2
= 0 + (11a - 107.8)(4) + (-9.8)(8)
= 44a - 431.2 - 78.4...
V(@11s)^2 = V(init.)^2 + 2AS(11s)
S(11s) = sqrt((V(@11s)^2 - V(init.)^2) / 2A)
= sqrt((V(@11s)^2 - 0) / 2(a - 9.8))
^ that will be the distance traveled during the first 11 seconds, with gravitational effect, in terms of total acceleration
S(15s) = S(11s) + V(@11s)t + .5At^2
= (the whole...
the gravity put an additional -9.8ms-2 to the acceration, so should i assume:
1. the acceration of the rocket's motor is actually a+9.8 in order to overcome the effect of the gravity? then the answer is 2.220+9.8 = 12.02 which is wrong according to the system.
2. when the motor stops, the only...
"launch a weather rocket" prbm
Homework Statement
A 1000 kg weather rocket is launched straight up. The rocket motor provides a constant acceleration for 11 s, then the motor stops. The rocket altitude 15 s after launch is 4600 m. You can ignore any effects of air resistance.
a) Acc. of...