I found that the acceleration of the system is 5 m/s^2. The forces acting on the 2 kg box are its weight, normal force from incline, and the reaction force from the 3 kg box. So would the force that 3 kg box exerts on 2 kg box be (3 kg)(5 m/s^2) which would be 15 N?
ok my bad. Yeah you're right: I guess Newton's laws don't exist in my world. I think I got confused when I resolved the weight into its components. That's what happens when you do a problem too quickly. Yikes indeed
Homework Statement
A force F pushes two boxes, box 1 and box 2 up an inclined plane of 30 degrees. If F=25 N and box 1 is 2 kg and box 2 is 3 kg, what is the force exerted on the 2 kg box by the 3 kg box. Assume no friction.
Homework Equations
F=ma.
The Attempt at a Solution
Since the...
Yes I meant the acceleration is -6 m/s^2. Could you clarify what you mean by "manipulating a quadratic"? Also, why would we have to know the intersection of a straight line and quadratic? Thanks
Homework Statement
A ball is shot out of a gun with an initial speed of 110 m/s. The acceleration of ball is -6 m/s^2 as it goes up an inclined plane of 1 m, which makes a 30 degree angle with the horizontal. Once the ball reaches the top of the inclined plane, it is launched off onto another...
Thank you man. I found the distance by finding the i and j hat separately. I got 4ti+(16/3)tj m. I plus in t=2 s and I get square root of 44.4. which is about 6.67 which is close to 7 m. Thanks a lot for helping me.
Homework Statement
Acceleration of a particle that begins at rest at the origin is given by a(t)=3ti+4tj, where a is in m/s^2 and t is in seconds. The particle's distance from the origin at time t=2s is what?
Homework Equations
You need to find velocity then distance
The Attempt at a Solution...