This has been solved hours ago on my own I was right and correct I'm just tired sometimes I even forget what the question is asking. I was tired but I got it correct it was just a blank out moment. That's why this post has been marked as solved no more assistance is needed but thanks anyways
1. At the instant of the figure, a 6.70 kg particle P has a position vector of magnitude 4.30 m and angle θ1 = 43.0° and a velocity vector of magnitude 3.40 m/s and angle θ2 = 32.0°. Force , of magnitude 7.40 N and angle θ3 = 32.0° acts on P. All three vectors lie in the xy plane. About the...
A star is 3.7 x 104 ly (light-years) from the center of its galaxy and is moving in a circle around that center at a speed of 170 km/s. (a) How long does it take the star to make one revolution about the galactic center? (b) How many revolutions has the star completed since it was formed about...
I’m not Martin Carr, as for I don’t understand anything of what he did if anything he confused me because I know conservation of energy must take place and I know what it looks like and he simply did not do that.
I’m Ella1777 and I asked the question and he attempted to give me a solution that...
The answer typed into Wileyplus must be 3 significant figures which rounds to 0.354 but only the final answer applies significant figures all the other work has to include all the digits
When working out the problem I have to quote all the significant figure or else points will be taken and it’s a risk to the wrong answer my professor says. When it comes to the final answer I do the sig figs and I typed in 3.0e7. Significant figures are usually the least of my problems it really...
So I just found kinetic energy only not the initial I’m assuming.
Adding KE and PE will get my initial KE?
Or do you mean
KEi+KEf=PEi+PEf ??
If that’s the case then did I just solve for KEf and how do I find PEi and PEf?
So I add KE: 3.0*10^7 to PE?
How would I solve for PE?
I’m sorry I’m...
I forgot to put my units on this post but I already have the correct units on my homework the units are not my concern since I understand them get it right the majority of the time.
As far as significant digits goes I have to write it all out our professor has stated that it’s the root of the...
Information Given:In 1956, Frank Lloyd Wright proposed the construction of a mile-high building in Chicago. Suppose the building had been constructed.
Question: Ignoring Earth's rotation, find the change in your weight if you were to ride an elevator from the street level, where you weigh 708...
Information Given:Zero, a hypothetical planet, has a mass of 4.2 x 1023 kg, a radius of 2.8 x 106 m, and no atmosphere. A 10 kg space probe is to be launched vertically from its surface.
Question: (a) If the probe is launched with an initial kinetic energy of 5.0 x 107 J, what will be its...
Information Given: In the figure, a square of edge length 17.0 cm is formed by four spheres of masses m1 = 4.70 g, m2 = 2.90 g, m3 = 0.800 g, and m4 = 4.70 g.
Question: In unit-vector notation, what is the net gravitational force from them on a central sphere with mass m5 = 2.90 g? Attempted...
Oh I see I tried it out and they got right around the same answer Thank you so much I understand now
when I used forces got : 10.687 degrees
when I used acceleration I got: 10.704 degrees
I typed this in several times into wileyplus as 10.7 degrees but I keep on getting it wrong. Why am I...
given: 128kg F1 = 28 N, F2 = 57 N, F3 = 38 N, θ1 = 30°, and θ3 = 60°.They are asking for the angle (measured relative to the positive direction of the x axis in the range of (-180°, 180°]) of the asteroid's acceleration?
The problem is displayed on quadrant I and IV
for vector notation I got...
A frictionless incline (the triangle below) is bolted to the floor so that it can not move. A block of mass m slides down the slope, which makes an angle with the horizontal.a)Draw a free-body diagram for the block, labeling all forces uniquely.
b)Describe all the forces listed above in the...