Wouldn't there be a relationship, so I would first have to differentiate it? Thus, that function would then be the one for the average cost per unit?
But it's asking for an actual value for x, which is throwing me off. Would I need to follow common procedure like other optimisation questions?
Your asking me what the question is asking in a simplified manner. I'm asking how to find the average. I'm unfamiliar with finding it with function specified.
I'm aware of what average means, though how would I find it with calculus? That, I'm not familiar with. I've done averages with actual numbers, not variables. Should I first differentiate it or do something else?
Homework Statement
REFER TO IMAGE
Homework Equations
SEE ABOVE
The Attempt at a Solution
I haven't been able to start this question. I'm wondering how to find the 'average cost per unit'.
Sorry that my handwritiing is too messy and scan isn't done right. Just trying to get this done ASAP.
(25-2x)(40-2x)
y=(25-2x)(-2)+(40-2x)(-2)
=-50+4x-40+2x
=-90+6x
x=15
Not sure what to next do.
radians question
sorry about that, if forgot to state my problem.
i was wondering how to get the inner angles of the big and small wheel.
i've been able to get 'alpha' and 'phi' but i don't know how to get 'theta' on the big wheel.
if you can explain how i can get that then i'll be able to...
Homework Statement
refer to question image
Homework Equations
refer to question image againThe Attempt at a Solution
refer to working out image
This is my brothers maths homework. He normally doesn't use online methods to request help and this is his first time.
Yeah that's true. I'm known for unintentionally doing so.
From what I'm gathering I write it like this: \frac{x^{3}}{12} to x^{3}12^{-1} and then go from their by normally differentiating twice over to get the second derivative - consequently finding x for the coordinate to substitute into...
I'm Rich! "New Energy Source"!
No, no. Just the measures the old lady took. Besides, it wasn't finding a friend more than being finding someone to continue the legacy. Does seem a little suspicious. And no, I'm not encouraging legal action.