Right folks, I've gone away n come back with an improved effort i think...
log3(10x-1) - 2 = log3(x2)
=log3((10x-1)/x2) = 2
= (10x-1)/x2 = 32 = 9
9x2 -10x + 1 = 0
=>x = 1, x = 1/9
Does this look correct to you guys or am I missing something again?
Thanks jedishrfu and everyone else...I'm going to walk away from it for a while n watch that video... n come back to it later tonight... 15 year old version of me would be lolling his head off at me now...if lolling was a thing back then
i'm just going round in circles here and getting nowhere I'm afraid
##\log_3(10x-1)=((log_3(10) + log_3(x)) / log_3(1))##
I understood when i had a common log base, i could divide all by that log base
hence ((10 + x) / 1) - 2 = x2
0 = x2 - x - 8
which doesn't give reasonable answers so i...
Thanks everyone for all the help...its been far too long since I've looked at any of this sort of stuff...
I now have it at
(log310x - log31) - 2 = log3x2
Then divide out the log3
10x - 1 - 3 = x2
0 = x2 -10x + 3
I've obviously done something wrong again as this gives pretty silly results :(
Hi folks,
I'm revisiting logs for the first time in a long time through distance education and I was wondering if someone could have a look over a question I've answered and let me know if I've done it correctly or if I'm way off please
Find x if Log3(10x – 1) – 2 = 2log3x
I instantly divide...
Could someone confirm that my thinking on this question is correct for me please? I'm basically just disregarding the Sin200πt and calculating the Vrms and Irms derived from from the 50 value at the start of the expression, i.e 50V. This seems incorrect to me, could someone just check my logic...
did i just miss that Sin200πt is representative of 1 volt?
Going by this conversion site, http://www.learningaboutelectronics.com/Articles/Peak-voltage-calculator.php#rms
Vrms = 25 / √2 = 17.7V
Irms = 17.7 / 40 = 0.4425 amperes
Does this look correct?
Thanks for your time and help...
Thanks for the reply PWiz...any formula I can find for these calculations seem to require a time.
The only one I can find without t is Vpeak = Vrms√2...=> Vpeak/√2 = Vrms
Vrms / R = Irms
I was thinkin maybe I could half the Vac given in the question, but that still involves a t variable...so...
Homework Statement
Sorry for what will likely be considered a noob question but I've been stuck on it for a while and its only at the start of my assignment :(
Simple circuit
Vac = 50Sin200πt, R1 = 40Ω
Calculate the value of the RMS current
Homework Equations
Vt = Vmax sin2πft = Vmax sinωt...