Recent content by ElBell

Homework Statement I am reading through my introductory course notes, and am given a question I don't understand how to answer. A rectangular tank contains fresh water inside it to a depth of 0.5m. The tank is 1m long and .7m wide. a) calculate gauge pressure at the bottom of tank b)...

Thanks for your help! What does everything think of what I have done here? Eo= Ei(R1/R1+R2) – (R3/R3+R4) Eo= 3V (100/100+150) - )200/250+300) = -.164V Let us change R1 to 125 ohms: Eo= Ei(R1/R1+R2) – (R3/R3+R4) Eo= 3V (125/125+150) - )200/250+300) = 0V

Homework Statement A bridge initially has resistances equal to R1=100ohms, R2= 200ohms, R3= 250ohms, R4= 300ohms. Determine output voltage at this condition for an input voltage of 3V. What is the bridge output if R1 changes to 125ohms? Homework Equations Havent been given any. I am...

Hi Everyone, Question: Mean is 0.252, standard deviation is 0.003, permitted tolerance of 0.246 to 0.258. What percentage of washers will be discarded. Attempt: I am so stuck. I have looked at my text and online for hours and know that it should be fairly easy but I am getting stuck...

OK thanks so much! This is what I now have: T at 0 degrees: R= 12/ 0.12 = 100 ohms T at 100 degrees: 100/2^(100/46) = 22.2 ohms R= 12/ 0.795= 15.094 ohms So: 15.094= 100/2^(T/46) 2^(T/ 46)= 100/ 15.094= 6.625 (T/46)log 2= log 6.625 T/46 = log(6.625-2) ? is this...

pat666, you are a champion :) Thankyou.

Thanks for your help so far: Can anyone help with part two? So far I have equations: W= 1/2kx^2 F=kx (so k= f/w)?? So: k= 3.6/ 0.096= 37.5 W= (1/2)(37.5)(0.096^2) W= 0.1728J ----does anyone know if this appears correct?

Stress= 3.6N/ (4* 10^-6) Stress= 900000 Strain= .096/ .80 Strain= 0.12 Y= 900000/ 0.12 Y= 75* 10^5 ?

I got .8 because it was .8 of a metre? previously i had 80cm written in but i guessed because we are using metres, .8 would have been the correct input?

OK, sorry for this, but now I am totally confused. Is the answer I had originally correct? 750? Or is my new answer correct? haha!?

Ooooh OK I see what you are saying. Stress= 3.6N/ (4* 10^-6) Stress= 900000 Strain= 900000/ .80 Strain= 1125000 Y= 90/ 1125000 Y= 8^-5 :( Now I am confused...and hopeless!

I know that at 0deg celcius it is 120mA and at 100deg celcius it is 540mA. Are these the figures I would use to calibrate, and how would I go about doing this? Thanks a lot :)

sorry, also forgot to mention that for some reason we are never given the lengths! I assume because we are using percentages I could just input the easiest figure and the result will always be the same??

Thanks for your help so far! I understand from your help on my last question that you don't square your numbers, but I havent. I thought I had to change my units to metres, so I changed 4 o (4*10^-2)? Maybe I should have just written 0.004 to save confusion. Am I right in even converting...

No I didnt receive an answer from teacher, I formulated it myself but it appears I didnt get it right! Thanks so much for your help, I know I am lacking the basic knnowledge for this but I am doing my best :)