sorry about the doc... i copied and pasted from a pdf so that might have something to do with it.
btw... you said \lambda_0 >> \lambda but it is actually the other way around... does that change anything?
lemme try that and i'll get back to ya. thanks alot
ok i found some direction to solving the problem but I'm still having trouble following the first expansion... see the attachment (Word) to see what I'm talking about.
thank
eric
My problem is to show that that where (lambda)>>(lambda_0) then Cauchy's Equation is an approximation of Sellmeier's.
Now I know generally how to solve it, but my trouble is in some of the expansions. The hint that is provided with the problem is "Write Sellmeier's Equation with only the...
hello all.
i'm working on a project and wondered if anyone had any information on the kuiper belt. actually the only thing i think I'm looking for is the sidereal period for one of these things. google didn't yield anything useful that i saw but i could have missed it.
btw we are using...
So does this mean that saying I = I_cm + ml^2 is the proper moment of inertia for the reel rotating about is edge (I_cm is the moi that we derived and then subtracted the four "negative masses")?
Basically, I'm bothered by not understanding what to do about the holes in the reel. And it's not...
ok so i did the substitution and substituted t into x and I've simplified is to
range = (v^2 *sin(2a)/g)*(1+ (1+2*g*h/(v^2 *sin(a))^1/2
is this the point at which i should take the derivative (w/ respect to a) and set equal to zero or is there a further simplification that i can make that i...
Thanks so much for a quick reply.
I thought I was supposed to find z in terms of x and then maximize x with respect to a and then solve to the form that the question is asking for. Is this incorrect? I still don't see it.
Problem: A cannon that is capable of firing a shell at speed V is mounted on a vertical tower of height h that overlooks a level plain below.
(a) show that the elevation angle a at which the cannon must be set to achieve maximum range is given by the expression:
csc^2 a = 2*(1 + g*h/v^2)
I...