14.4ohms
L=0.0764H
correct?
The instructions were:
Gradually increase the load from the original value. You may increase either P, or Q, or both. Monitoring the load voltage.Your objective is to maximize the apparent power (|S|=sqrt(P2 +Q2 ) of the load while ensuring that the load RMS voltage...
I believe so. The instructions seem to hint that we are supposed to try random values of P and Q (real/reactive) until we find a maximum within 114<V2rms<126.
Is there a way to calculate the maximum apparent power by hand instead of trying out random values?
Do you mean Load 2 in the picture?
If yes:
Nominal Voltage: 120
Nominal Freq: 60
Active Power (W): 1000
Inductive Reactive Power (Q): 500
I think we were supposed to change Active/Reactive power in the parameters to see how "high" we can get while keeping in the 114<V2<126 range for load voltage...
Homework Statement
given a linear transformer rated for 50kVA, 11000V/120V
How do I find the maximum apparent power? The prompt is to maximum apparent power while keeping the Load RMS voltage between 114V and 126V.
Vsource has a peak voltage of 11000*sqrt(2).
The circuit looks something like...
I am plugging in the original total real power and total reactive power. I cannot get the original value of capacitance.
Edit:
I used 576-430.8i instead and got the original capacitance value. How do I solve for C if I don't have a "defined" real power to solve for? Do I simply divide that by 2...
Ok, thanks!
Going back to this:
##Z = R1 + ZL + \frac{R2*ZC}{R2+ZC}##
Total complex power would be V^2/Z, where Z is the above right?
How would I solve this using algebra?
I want to reduce reactive power by 50%
This is my work:
##Q_{original}=430.8##
##Q_{desired}=215.4##
##Q_{delta}=215.4##
##X_C=\frac{V_{rms}^2}{Q_{delta}}=\frac{120^2}{215.4}##
##C=\frac{1}{X_C*2*pi*60}=3.967e-5##
Where would I stick this capacitor in the circuit to get my desired reactive...