Recent content by Dustyneo

I think I grasped where the mistake was . So I proceeded to only get the mass amount for C and H. (0,2829 g CO2)(mol CO2/44,0 g CO2)(mol C/mol CO2 )(12,0 g C/mol C) = 0,0772 g C (0,1159 g H2O)(mol H2O/18,0 g H2O) (2 mol H/mol H2O)( 1 g H/mol H) = 0,0129 g H Then substracting the addition of...

Ok. In order to fill the values for a, c and d, I did these calculations, Finding the amount of menthol molecules, (0,1005 g C10H20O ) (mol C10H20O /156,09 G C10H20O) (6,02 X 1023 C10H20O molecules / mol C10H20O ) = 3,88 x 1020 menthol molecules CO2 molecules (0,2829 g CO2) (mol CO2/44,0 g...

Made a calculation mistake for H, the corrected value is 0,0129 (0,1159 g H2O) (mol H2O/ 18,0 g H2O) (2 mol H/ mol H2O)= 0,0129 mol H For O, I also noticed that the actual number is closer to 0,00644: (0,1159 g H2O) (mol H2O/ 18,0 g H2O) ( mol O/ mol H2O) = 0,00644 mol O

Homework Statement Menthol, the substance we can smell in mentholated cough drops, is composed of C, H, and O. A 0.1005-g sample of menthol is combusted, producing 0.2829 g of CO2 and 0.1159 g of H2O. What is the empirical formula for menthol? If menthol has a molar mass of 156 g/mol, what is...