Recent content by Dumbledore211

Is f(r) = f(x)i + f(y)j +f(z)k what being meant in the above stated problem?

Homework Statement The problem states that it is required to prove that ∇f(r)=f'(r)R/r where r is the vector field Homework Equations ∇=(∂/∂x)i + (∂/∂y)j + (∂/∂z)k R= xi + yj +zk r = √(x^2+y^2+z^2) The Attempt at a Solution The trouble that I am having with this problem is the inability to...

∞Homework Statement If Lim f(x) and Lim g(x) both exist and are equal x→a x→a then Lim[f(x)g(x)]=1 x→a Homework Equations No relevant equations are required in this problem. To determine whether the statement is true or false [/B]The...

√Homework Statement Show that the gravitational field due to thin uniform circular plate of radius a at point distant R from center and on the axis passing through the center and perpendicular to the plane of the plate is given by E= -2πGρ[1-R/(a^2+R^2)^1/2] Homework Equations F= GMm/r^2...

You have missed out on crucial piece of information which the value of is 1.60m/s^2 as the event is taking place on the moon

@Andrew mason It is just not me. Almost all my textbooks use R to denote the normal reaction force

The 30 degrees is actually the angle created by the arc with the horizontal plane. So, the vertical force in this case is the normal force i.e R=mgcos30 and the horizontal component of the forces in this case are as follows mgsin30-fs=mv^2/r or...

Homework Statement A car is traveling round a bend which is banked at an angle of 30 to the horizontal. The bend is assumed to be in the shape of an arc of a circle of radius 80m. the surface of the road is rough and the coefficient of friction between the tyres of the and the surface of the...

@Paisiello I have sent an attachment file and see if the overall free body diagram of the problem is correct. This problem is seriously flying over my head and one of the problems I have struggled with the most.. I still don't get how I can take the separate sums of each segment and establish a...

So, the two tensions are identical because the third mass is connected to the axis of the pulley which means T1=T2 in this problem. So, we have four equations and we still need another one...

@dauto There is only one string attaching all the three masses.. I guess I won't be able to solve it on my own but thanks anyway

@Paisiello2 So the equation for 3m should include both T1 and T2 like this 3mg-(T1+T2)=3ma3. The other two equations for the other two masses T1=ma1 and T2=2ma2. We need two more equations to solve for a1, a2 and a3 and what are they going to be like?

@haruspex how can one equation relate the three different accelerations if the tension is same for all of them? Can you please explain?

That means the whole system is in motion. The mass with 3m is fixed at the center of the pulley or the string and the two masses m and 2m are constantly changing positions in a loop I guess. So the equation for the 3m mass is 3mg - T2= 3ma2. The equation for m is T1=ma1 and for 2m T2= ma2...