Heya's
how would one go about spanning a vector say 'u' onto a plane spanned by vectors v1 and v2.
I have a formula for projecting a vector onto say a subspace w:
projw(u) = <u,v1>v1 + <u,v2>v2 + ... <u,vn>vn
But I'm unsure how to use this for when I need to project the vector onto a...
Heya's
Having some problems with the following question:
Trimethylacetic acid C_4 H_{11} COOHis a weak monoprotic acid. When 0.0010 mol of Trimethylacetic acid was dissolved in 100mL of water, the concentration of trimethylacetic ion was found to be 3.0 \times 10^{ - 4} mol.L^{ - 1}
a)...
Hey, I need some help with the following question:
A sample of 0.1964g of Quinone (C6 H4 02, Relative Molar Mass = 108.1) was burned in a bomb calorimeter that heas a heat capacity of 1.56 kJ/M. The temperature in the caolorimeter rose from 19.3 to 22.5 degrees celcius.
(a) write a...
The exhaust gas from a car is tested and found to contain 8% by volume of carbon monoxide. If the molar volume of CO at SLC = 24.4 L/mol, what is the mass of carbon monoxide in 1L of exhaust gas?
I'm very new to these calculations and am unsure how to approach it.
Heya's
Im a bit confused reguarding gravitational potential energy.
I've seen 2 different calculations
U(h) = mgh
where h is the height above the ground.
and
U = -GMm/r (off the top of my head, havnt got my notes here with me right now)
Could anyone help clear this up for me? Why...
Here is the problem:
{\mathop{\rm Im}\nolimits} \int {e^{x(2 + 3i)} } dx
One sec, I'm having another go at it.
= {\mathop{\rm Im}\nolimits} \int {e^2 } e^{3ix} dx
= {\mathop{\rm Im}\nolimits} \int {e^2 } [\cos (3x) + i\sin (3x)]dx
\begin{array}{l}
= \frac{{ - e^2 \cos...
Think I've worked it out for myself.
Method was sort of wrong.
Once I have Grad F, all I need to do is sub in the values of the point and It will give me the normal vector and from that I can work out the equation.
I think that's right.
I'm having trouble working out the tangent plane of an equation at a specified point (4,1,-2)
The equation being 9x^2 - 4y^2 - 25z^2 = 40
now
\nabla f = (18x, -8y, -50z) yeh?
Just reading off this should give us the normal vector shouldn't it? (18,-8,-50)
and from that we can work out...