dark_matter_is_neat's latest activity

Following the calculation done in section 5.3 of Schwartz's QFT and The Standard Model, the matrix element, M, should have two...

So to get the partition function I do the integral ##\int \alpha E^{3} e^{(B_{0}-B)E} dE##, which substituting in ##/Delta B = B_{0} -...

But this is not what you should get, you should get ##-i\hbar m(x+y+3z)f(r)##, for all combinations of ##x,y,z##. You cannot try to...

You can, of course, brute force it. However, you will get a long way here by considering ##\psi(\vec r) = (\vec v \cdot \vec r) f(r)##...

Yes, this a valid solution. More generally and easier to see is the following: Assuming that ##\psi = (\vec v \cdot \vec r) f(r)## for...

By looking adding equation 1 to equation 3 you get: ##3n_{x}-3n_{y} = 2m## which multiplying each side by -1 is ##3n_{y}-3n_{x} = -2m##...

I ran through the math and you're just going to end up with essentially the same system of equations as before, since ##\varphi## is the...

I would rewrite the given wavefunction as a linear combination of spherical harmonics ##Y_1^m## and then operate on it with...

Thank you for fixing the LaTeX. How is ##L## defined here?

So rewriting ##\psi(\vec{r})##, ##\psi(\vec{r}) = rf(r)\sqrt{\frac{2\pi}{3}}[(i-1)Y^{1}_{1} + \frac{6}{\sqrt{2}}Y^{0}_{1} +...

##L=-i\hbar(\vec{r} \times \nabla)## is the angular momentum operator.

First I calculated ##(\vec{n} \cdot L) \psi(r) = -i\hbar(n_{x}(3y-z)+n_{y}(z-3x)+n_{z}(x-y))f(r)## and then tried to solve for ##n_{i}##...