Salaam Chris
Yes I tried to cut & paste some latex and I did not see any rendering of the symbols and thought I was doing something wrong.
I will start a new thread shortly with your write up and ask some questions.
Sorry about my slowness around her
and thanks for the resposne
D
Salaam Chris
I am ready to type in some equations and ask you questions, however no matter where I get the equations i.e. from which editor or even your own, I cannot cut and paste into this text box.
I know I am doing something stupid, is there a trick into pasting equations here...
Salaam Chris
Toiling over the math to get all the concepts right prior to running my mouth again. got some of the arXiv papers to help out.
A bit more time.
As we say in Farsi Dasteh Shoma raa boosidam, thank you for such wonderful help.
I will study and get back to you, give me a day or so
Thank you again
Dara
Dear Stingray
Right, what you wrote about ds2 is what I meant all along, I will try to learn how to use the equations in this forum instead of babbling :)
D
I meant ds2 (squared) is invariant not the components. I just don't believe that almost all symmetric 4x4 with non-vanishing det do the job.
But again your point was really nice. you may suffer by seeing me asking more questions :)
D
Hello Stingray
I believe in your latter statement about the generation of ANY metric from some matter distribution. I guess that is due to the fact that the matter distribution appears on one side of the equation and the curvature metric on the other side. So you can drive the metric by the...
Hello Chris
you can make fun of me as u like it won't reduce me sincerity and effort to learn GR. It only reflects upon your character.
INVARIANCE is with regards to COORDINATE TRANSFORMATIONS. This is a standard lingo u can find in all the books dealing with GR or related material.
> but...
Dear Chris and Stingray
What I mean by the metric is an invariant metric that satisfies the usual tensorial transformations. Not all functions can support that, only a few to my knowledge e.g. the euclidean length.
You may perturb a tensor to still act as a compliant vector, to be a solution...
Dear robphy
I cannot get the files! No login/password and I could not find them in another place on the net.
Any suggestion or does anybody has a copy?
D
Thanx
Ok this is what I need to find out.
If there is a fundamental tensor gij, for every infinitesimally small e can I find another fundamental tensor g'ij that satisfies: |gij - g'ij| < e at least for a local neighborhood if not for the entire space.
I will check the references as...