I'm a little doubtful because this solution seems trivial, but for the sake of completeness, here is my work:
f\left( z \right)=\sum_{n\; =\; 0\; }^{\infty }{\frac{1}{n!z^{n}}}
g\left( z \right)=\frac{1}{z^{5}}\left( \sum_{n\; =\; 0}^{\infty }{\frac{\left( -\frac{1}{z} \right)^{n}}{n!}}...
OK I believe I've solved the problem... both these functions f and g should have essential singularities at z=0, and their product has a pole of order 5 at zero:
f\left( z \right)=e^{\frac{1}{z}}
g\left( z \right)=\frac{1}{e^{\frac{1}{z}}z^{5}}
Would anyone mind confirming this...
Homework Statement
Find two analytic functions f and g with common essential singularity at z=0, but the product function f(z)g(z) has a pole of order 5 at z=0.
Homework Equations
Not an equation per say, but I'm thinking of the desired functions in terms of their respective Laurent...
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