I tried something along those lines.
cos (a*x^2 + b) = cos (a*(x+T)^2 + b)
Hence,
a*x^2 + b + 2* PI*k = a*(x+T)^2 + b, where is k is an integer.
Which reduces to,
2*PI*k = a*2*x*T + a * T^2
So T is function of x.
So the function is not periodic.
But let's take an...
Hi all,
Hope some here can help me with this math problem.
Given,
y1 = ax^2 + b.
y2 = cos (y1).
where a and b are constants. Is y2 periodic with respect to x.? Visually using example grpah, seems to be periodic. How do u find the exact period of such a function?
Thanks in advance...