So based on the circuit and resistors etc, we've gotten equations for KVL. How do those equations translate into the other equation i5 = i1 + i2 + i3? I have another tutorial on this tonight but I really want to make a bit more progress.
For my own review I know that:
Right Loop: 40i2 -80i3 = 0...
OK, I'll try again...
Right Loop: 40i2 - 80i3 = 0
Middle Loop: 20i1 - 40i2 = 10
Left Loop: 10i5 + 20i1 = 10
Outside Loop: 10i5 + 80i3 =10?
Power Dissipated is
P=V^2/R I think. Is that the right formula?
Voltage for each resistor would depend on which loop it's for?
So when I write out that
i1 = 40i2 + 20i1 = 10
i2 = 80i3 - 40i2 = 0
i3 = 40i2 - 80i3 = 0
i5 = 10i5 + 20i1 = 10?
I think I confused myself with the different equations...:redface:
So now that I have the equations and have some understanding, what exactly does that tell me about the currents? And how do I confirm this with power dissipated?
I thought that about the voltage but wasn't sure. So the right and middle loops have no voltage immediately in them so they have to balance out. But because on the left there's 10 volts going directly into that loop, the equation has to = 10? Is that right?
The outside loop is...
10i5 + 80i3...
So the right loop ie the 80Ω and 40Ω i3 and i2
=80i3 - 40i2 = 0 OR i2 = 2i3
Middle is the 20 and 40 ie i1 and i2. So
i1 = 2i2 40i2 - 20i1 = 0
The left? Is there not voltage already there on the left as 10 volts is Vs.
So I5 = 2i1
10i5 - 20i1 = 0?
lol, Well, I thought that 2 x 20 =40 and therefore 40-40=0. It all comes back to thinking things = 0. So is this to determine the current or the voltage? :confused: