i understand it is 2/3 the speed of light but am I using the right equation?
using this equation I found that one second passes for A as 1.34 seconds passes to person B. But not sure how the book gets 3.92s as the answer
I have the attached equation
but when I plug it, I don't get the same answer as in the back of the book...
Here is the question
Two observers, A on earth, B in a spacecraft whose speed is 2.0X10^8 m/s both set their watches to the same time, when the ship is abreast the earth.
How...
I have the attached equation
but when I plug it, I don't get the same answer as in the back of the book...
Here is the question
Two observers, A on earth, B in a spacecraft whose speed is 2.0X10^8 m/s both set their watches to the same time, when the ship is abreast the earth.
How...
Can someone check my work and see if I am on the right track please?
the problem is:
if r(t) = <e^t, cost, sint> compute integral from pi to 0 of r(t)dt
so I split it into three integrals, and ended up with (e^(pi) - 1)i + (0)j + (2)k
does this sound right?
Thanks
here is the problem, and I can't seem to get very far,
compute the length of r(t) = <3t, 4cost, 4sint> from t=0 to t=1
i know the formula is integral from 0 to 1 of length of r'(t)
but I keep coming up with 5, and it doesn't seem right, can someone please confirm or deny this. Thanks
its a curve of that function. I'm not sure on the range, I guess just enough to show the pattern. I believe it is a cos sin circle coming out the x axis.
Can someone give me a couple hints to get me started on this problem, I am not sure where to go next.
Infinite line of charge has charge per unit unit length 4.8*10^-6 and lies along the x axis. A second uniform line of charge with charge/unit length
-2.4*10^-6 is parallel to the x-axis at...
I've been thinking about this problem for a while now, and I can't get it to work out. A 9.6X10^-6 C point charge is at the center of a cube with sides of length .5m What is the electric Flux through one of the six faces of the cube? I know the answer is 1.81X10^5 but I can't figure out how to...