So it would be ## |B| = \frac μ 2 \frac {IR^2} {(R^2+z^2)^{3/2}} ## and then since there are two coils I would use just have ## |B| = μ \frac {IR^2} {(R^2+z^2)^{3/2}} ##
I tried ## |B| = 1e-7*\frac {3A*0.03m^2*2π}{(0.03m^2+0.065m^2)^{3/2}} ## and then multiplied it by 2 to incorporate both rings and got 9.247e-6. It was wrong
Homework Statement
Two thin coils of radius R = 3 cm are d = 13 cm apart and concentric with a common axis. Both coils contain 10 turns of wire with a conventional current of I = 3 amperes that runs counter-clockwise as viewed from the right side (see the figure).
(a) What is the magnitude...