Using 893kg/m3 as the density for citral, and 1.12g/cm3 as the density for diethyl phthalate, I have:
5.866*10^-3 moles citral and 4.536*10^-2 moles diethyl phthalate in 10mL of 10% solution
The mole fraction for citral is 0.1145
What do I need the moles of citral in 10grams of solution for?
We would like the mass concentration, and then to eventually convert this to ppm.
The solution can be considered ideal.
10% is by mass (1mL pure Citral in 10 total mL of Diethyl phthalate)
The air in the vial was initially at 1atm
Sure.
Given 10mL of 10% Citral solution (dissolved in diethyl pthalate) ( vapor pressure 0.2 mm of Hg (@ 20°C)) in a closed 20mL vial, what is the concentration of the air above the liquid in parts per million.
How would you calculate the concentration of a vapor above a liquid in a sealed jar in parts per million? Supposing that the liquid is a 10% solution of X with known vapor pressure.
We've gotten to this point:
1ppm = 1mgX/ g solution
1ppm = 1mgX/1mL solution (assuming it's water and water has...