I can’t just plug in any p value and see if it works. Is there a way to prove this algebtaically or with an inequality? It would make sense that the probability of p would be more than 0.5 so that team A can have an advantage but I can’t just blatantly say that without proof..
A team can't win more than 4 games in a best of 7 series. The series would have stopped at when a team first reaches to 4 wins. Why would setting up the probability that Team A wins at least 4 games when at most you can win is 4 in a best of 4 of 7 game series?
Since we're trying to find the kth success(4th game won) on nth trial(can be 4,5,6 or 7th game), why wouldn't the negative binomial distribution work for this problem? What distribution should I use?
My attempt
I used negative binomial to solve the problem, however I'm left with a polynomial that is difficult to solve? Is there any other way to approach this problem?
I used the inequality because I'm trying to find the range of p. Since the probability of winning the series for team...
With the amount of money you can earn with an engineering degree, you can pay off that debt in 2-4 years! I'm currently in UWO right now and one of the reasons I chose it was for the university experience and to tell you the truth… I would've been as happy if I were to stay in Mississauga and...
Why not both? Do 2 years @ Mac and than the last 3 years @ UofT. That way, you'll spend somewhere in-between 60 grand to 120 grand AND have the university experience.
Homework Statement
How many values of k can be determined in general, such that (k/p) = ((k+1) /p) = 1, where 1 =< k <=p-1?
Note: (k/p) and ((k+1)/p) are legendre symbols
Question is more clearer on the image attached.Homework Equations
On image.
The Attempt at a Solution
I've tried...
Homework Statement Homework EquationsThe Attempt at a Solution
The superimposed diagram shows that the probability of a noncommunicable disease in a underdeveloped country is 0.37. But it's not correct…
I tried 0.56*0.78 = 0.44 as the probability of a noncommunicable disease in a...
1) 3^(2^a) + 1 divides 3^(2^b) -1
2) If d > 2, d ∈ N, then d does not divide both 3^(2^a) + 1 and 3^(2^b) -1
Attempt:
Set b = s+a for s ∈ N
m = 3^(2^a). Then 3^(2^b) - 1 = 3^[(2^a)(2^s)]-1 = m^(2^s) -1
Thus, m+1 and m-1 divides m^(2^s) -1 by induction.
If s = 1, then m^(2^s) -1 = m^2 -...
Homework Statement
A college student wants to start a new savings account with an initial balance of $0. He plans to save money at a
continuous rate of $700 per month. Additionally, every month he plans to increase this rate by $7. (Such
that for example in month 3 he is saving at rate $721...
That's all that the question gives. There's no initial conditions given either. I assumed that the additional force would equal 100v^2 as it says it's proportional. But you're right, the units don't match up.. Could it be possible that the units are hidden within the coefficient of v^2?