the fraction gets smaller, but don't we end up adding that to the value of c??well if a/(x-b)^2 +c
let a=1 b=1 c=2
so we get
1/(x-1)^2 +2
lets make x =2
we get
1/1 +2 ... that's 3... wait am i doing something wrong?
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oh wait is because in the above a is negative.. so...
I'm stuck at understanding why +c is the horizontal asymptote. Can someone please explain this? I get that the vertical asymptote is relating to (x+b), because the denominator cannot=0. But why does this kind of graph have a horizontal asymptote to begin with?
Can someone explain how these graphs are drawn. How does the value of p/q affect this graph? How does the domain and range change? How are the asymptotes found?
The below is an image about what I'm talking about:
Here is a question the deals with this type of graph (no idea how to solve it...
Can someone explain the following:
How does changing the value of p/q affect the drawing of the graph (so domain/range/shape etc)
What makes this graph an odd function?
How to work out asymptotes?
Heres a picture so you know what I'm referring to:
And below is a question dealing with this...
Can someone explain why the answer is D
a < 0 because it finishes downwards
e < O because the y-intercept is in the negatives.
b, & d = zero (but i don't get this)
c is supposedly > 0 (nor do i get this)
According to the solutions the graph is an even function, and symmetrical about the...
There are a couple of things i didn't get in your explanation, and its due to my lack of vocab in calculus. :P
this derivative has a root at x=0 (what do you mean root?)
this roots is of even multiplicity (again, what is root/ multiplicity?)
from the second derivative test for relative...
Hey guys, I'm interested in having someone who likes maths to discuss maths questions/solutions/concepts with myself.
This is just to improve my understandings over the year.
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I'm interested in studying on...
Can someone explain the link between the turning point (local max, min & stationary point of inflection) and it's relationship to derivatives.
Let me clarify what I understand (feel free to correct me).
If we derive an equation and let it = 0, the value of x is some kind of turning point...