After watching the video recommended by @erobz, I could how your words complement the pictures. The golf ball compressing into a weird shape and decompressing into another shape is a sight to see!
@Steve4Physics No, I didn't mean lower! Thanks for catching that.
You say "I found" but it seemed a trivial step to go from the change in momentum to the impulse, since they are clearly related in the equation (impulse = Fdt = dp).
Here's a shot at finding the value with the impulse as is...
@kuruman Thanks for the reassurance! And it turned out as you expected to my delight :). Your quote "Doing physics without math is like cooking food without heat." made me grin ear to ear and chuckle.
Thanks @Steve4Physics ! Thanks for breaking the question down and rewriting it for me ! I see that the ball would end up with lower velocity to the clubhead's 18 m/s, especially after following through with Nugatory's suggestion and getting the "correct" outcome.
I do have another question. You...
Thanks Nugatory!
I have bolded the edits based on what I think you wrote.
(prior p of clubhead) + (prior p of ball) = (following p of clubhead) + (following p of ball)
0.225*30 + 0.05*0 = 0.225*18+0.05*v_f,b (where v_f,b is the following speed of the golf ball)
6.75 = 4.05+0.05*v_f,b
2.7 =...
I have done the first two parts of this question.
✅(i) Find the clubhead's change of momentum. ( dp = p_f - p_i = (0.225*18 - 0.225*30) = -2.7 kg ms^-1 )
✅(ii) Find the impulse given to the golf ball. (F dt = dp = 2.7 Ns from part (i) with just a change in the units. Because of the...