Recent content by chromium1387

Homework Statement An ideal monatomic gas has an initial pressure of 3 atm, an initial volume of 1 L, and is at an initial temperature of 90 degrees Celsius. It first expands isothermically to 2 L and is then cooled isobarically to a point where it is adiabatically compressed to its initial...

okay. :)

I don't know.. haha. It's just incorporated into the density, right? :P

Ohhh.. My bad. Silly algebra mistake. And that makes sense. I'm just used to placing one end at the origin. Sooo, after I integrate and everything, I get \frac{MA}{b}? Thanks for your reply!

Homework Statement A thin rod extends along the x-axis from x= +b to infinity. It has a non-uniform linear mass density of A/x^{4} where A is a constant with units of kg m3. Calculate the moment of inertia of the rod for rotation about the origin. Homework Equations The Attempt at a Solution...

yesyesyes! thank you! crazy how overlooking one silly thing can mess things up!

righttt! so then i'll just have n/n+1.

i, uh, I'm not really sure.. i just canceled things. like the 1*3*5*... cancel. the 2n stays. the x^(2n+2) / x^2n make x^2. the n!/(n+1)! make n+1. the 2^n/2^n+1 just gives me 1/2. which cancels with the 2 in 2n. so i got n/(n-1)(2n-1) all times x^2. :s

lim n\rightarrow\infty |\frac{1*3*5*...*(2n)x^{2n+2}}{2^{n+1}(n+1)!}*\frac{2^{n}n!}{1*3*5*...*(2n-1)x^{2n}}| =lim n\rightarrow\infty |\frac{n}{(n+1)(2n-1)}|x^{2} which, by l'hopital's rule is: lim n\rightarrow\infty |\frac{1}{2n+2(n+1)-1}|x^{2} =0

Okay. Thank you!

Thanks for your response! :) Okay, so does this mean that my radius and interval of convergence are correct? This should be easy enough then. Thanks!

Homework Statement a. Find a power series expansion for arcsin(x) centered at 0. b. Find the radius of convergence and interval of convergence of the power series in a. c. Choose an appropriate value of x to plug into the power series found in a. to find a series that converges to...

oh, wow. i was definitely thinking backwards for some reason. thank you for replying to my very silly question!

Homework Statement We did this question today in class, but looking back at it, I'm kind of confused. Two identical dumbbells are formed by placing equal point masses at either end of two identical light (ie. massless) rods. The rods are pivoted so that dumbbell A rotates around the centre...

Apparently i didn't search well enough before I posted. Thanks for responding to my post, which I'll now delete. And yes, I do go to Mac!