Recent content by Chestermiller

Where was the temperature measured in the experiments? Was the placement of the thermocouple consistent in all 3 cases (i.e., the same distance above the bottom)? How do you know that the induction heating rate of the pots was the same in all the cases? Would placing all four pots on the same...

In the direction parallel to the plate movement.

In this case, you can use lubrication theory in which the plates are treated as "locally parallel", and in which. although over a period of the sinusoid, the pressure change is zero, the pressure varies locally axially, and there is a net axial flow (although it is not the value that would be...

Let ##dQ_H## be the differential increments of heat received by the engine during the heating part of the cycle, ##dQ_C## be the increments of heat rejected by the engine during the cooling part of the cycle, ##T_{max}## be the maximum temperature during the heating part of the cycle, and...

Yes. But as long as the sinusoidal length period. is very large compared to the height of the channel, the vertical components of velocity will be small.

The equation for the pressure gradient in the tube goes like: $$\frac{dP}{dz}=-\left(\frac{4}{D}\right)\left(\frac{1}{2}\rho v^2\right)\left(\frac{0.0791}{Re^{0.25}}\right)$$where we have assumed that the flow is turbulent and the Reynolds number lies in the range 2000 < Re < 100000. The term...

The viscosity of helium at 20 C is 0.0002 Poise and, at 2 bars gauge, its density from the ideal gas law is 0.492 gm/liter. So 15 LPM, the mass flow rate is 7.39 gm/min = 0.123 gm/sec. At this mass flow rate, the Reynolds number for a 9 mm tube is $$Re=\frac{4\dot{m}}{\pi \mu...

What is the mass flow rate at 2 bars?

It doesn’t.

Volume per unit mass, For an incompressible fluid,fhe equation of state is degenerate.

Yes, but for a compressible fluid, the equation of state says that the pressure is independent of specific volume.

All the equations you have written are the incompressible case.

If you are considering the liquid water as incompressible. then its specific volume is independent of pressure, and the static pressure (as you call it) is equal to the hydrostatic pressure at all depths. The equation of state for an ideal gas is $$P=\frac{\rho RT}{M}$$where M is the molecular...

Your equation for the hydrostatic pressure is incorrect if you are allowing the water to have a pressure which varies with specific volume (i.e,. your 'static pressure relationship). That is, if the water is considered compressible.

If I understand you correctly, the hydrostatic pressure must match the static pressure at all depths in the glass.